SOLUTION: I have a word problem, think I have an answer. Could you let me know for sure. A chemist is making 200 Liters of solution that is 62% acid. He is mixing 80% acid solution with a 3

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Question 130390: I have a word problem, think I have an answer. Could you let me know for sure.
A chemist is making 200 Liters of solution that is 62% acid. He is mixing 80% acid solution with a 30% acid solution. How much of the 80% acid solution will he use? I have 68 liters. Could you let me know if this is correct, thank you I really appreciate the help.
Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website!
here is a "rule of thumb" for mixture problems
__ the average of 80% and 30% is 55% __ this is what you get mixing them in equal parts
__ since the mixture is supposed to be 62%, it must be more than half of the 80%
__ so the amount of 80% is more than 100L

let x="amount of 80%", so 200-x="amount of 30%"

(80%)(x)+(30%)(200-x)=(62%)(200) __ .8x+60-.3x=124 __ .5x=64