SOLUTION: A JAR CONTAINS 3 WHITE MARBLES, 4 RED MARBLES,AND 5 BLUE MARBLES. FIND THE PROBABILITY OF CHOOSING THE GIVEN MARBLES WITHOUT REPLACEMENT. 1. P(RED/BLUE) 2.P(BLUE AND BLUE)

Algebra ->  Probability-and-statistics -> SOLUTION: A JAR CONTAINS 3 WHITE MARBLES, 4 RED MARBLES,AND 5 BLUE MARBLES. FIND THE PROBABILITY OF CHOOSING THE GIVEN MARBLES WITHOUT REPLACEMENT. 1. P(RED/BLUE) 2.P(BLUE AND BLUE)      Log On


   

Question 130103: A JAR CONTAINS 3 WHITE MARBLES, 4 RED MARBLES,AND 5 BLUE MARBLES. FIND THE PROBABILITY OF CHOOSING THE GIVEN MARBLES WITHOUT REPLACEMENT.
1. P(RED/BLUE)

2.P(BLUE AND BLUE)
Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
A JAR CONTAINS 3 WHITE MARBLES, 4 RED MARBLES,AND 5 BLUE MARBLES. FIND THE PROBABILITY OF CHOOSING THE GIVEN MARBLES WITHOUT REPLACEMENT.
1. P(RED/BLUE)
2.P(BLUE AND BLUE) 
How many marbles are you drawing?  Two?

What does P(RED/BLUE) mean? 

Does it mean the probability of getting
a RED and then a BLUE?  Or does it mean the probability of getting 
a BLUE 2nd given that you got a RED first?

P(RED first AND BLUE second) = %284%2F12%29%285%2F11%29 = 5%2F33
  
P(RED 2nd GIVEN BLUE 1st) = P(RED 2nd | BLUE 1st) = 4%2F11

P (BLUE first AND BLUE 2nd) = %285%2F12%29%284%2F12%29 = 5%2F36

If these are not what you're looking for, then post again giving
all of the exact instructions, and I'll explain my answers better.

Edwin