SOLUTION: Hi! Another word problem I am having trouble with. So it says: *Erins age is 3 times Warren's. In 4 years she will be twice as old as he will be. How old is each now?* Please

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Question 129946This question is from textbook algebra
: Hi! Another word problem I am having trouble with. So it says:
*Erins age is 3 times Warren's. In 4 years she will be twice as old as he will be. How old is each now?*
Please and Thank You=) This question is from textbook algebra

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Erin's age is three times Warren's age. This can be expressed as:
E = 3*W
In four years, she (Erin) wil be twice as old as he (Warren) will be. This can be expressed as:
E+4 = 2(W+4) Substitute the E = 3*W from the first equation and solve for W.
3*W+4 = 2(W+4) Simplify and solve for W.
3W+4 = 2W+8 Subtract 2W from both sides.
W+4 = 8 Subtract 4 from both sides.
W = 4
Warren's present age is 4 years.
Erin's present age is 3*W = 3(4) = 12 years.