SOLUTION: A student walks and jogs to college each day. She averages 5 km/h walking and 9 km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far
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-> SOLUTION: A student walks and jogs to college each day. She averages 5 km/h walking and 9 km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far
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Question 129861This question is from textbook Introductory Algebra
: A student walks and jogs to college each day. She averages 5 km/h walking and 9 km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far does the student jog? This question is from textbook Introductory Algebra
You can put this solution on YOUR website! 5T+9(1-T)=8
5T+9-9T=8
-4T=-1
T=-1/-4
T=1/4 OR .25 HOURS FOR THE TIME WALKING
1-1/4=3/4 OR .75 HOURS JOGGING.
PROOF
5*.25+9*.75=8
1.25+6.75=8
8=8
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