SOLUTION: I need help with finding the vertex of the parabola f(x)=3x2-18x+32

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Question 129812: I need help with finding the vertex of the parabola
f(x)=3x2-18x+32
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=3x2-18x+32
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The vertex occurs where x = -b/2a = 18/6 = 3
and f(3) = 27-54+32 = 5
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Vertex: (3,5)
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C3x%5E2-18x%2B32%29
Cheers,
Stan H.