SOLUTION: There are two boxes labeled “A” and “B.” Note on the box “A” reads: The note on the box “B” is true and gold is in the box “A.” Note on the box “B” reads: The note on the box “A” i

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Question 129798: There are two boxes labeled “A” and “B.” Note on the box “A” reads: The note on the box “B” is true and gold is in the box “A.” Note on the box “B” reads: The note on the box “A” is false and gold is in the box “A.” You have only one chance to open a box to get gold. Which box would you open and why?

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
I'm going to establish some symbology for this discussion.
N%5BA%5D is the note on A, N%5BB%5D is the note on B, G%5BA%5D is "the gold is in box A", G%5BB%5D is "the gold is in box B"

Also, since I can't figure out how to render a vinculum on this system, I'm going to denote the idea of 'Not' by prefacing the above symbols with an n. nN%5BA%5D = 'not the note on A' which is equivalent to 'the note on A is false' Also & means 'and', v means 'or', T means True, and F means False. And lastly, a => b, means 'if a then b'

N%5BA%5D=N%5BB%5D&G%5BA%5D

N%5BB%5D=nN%5BA%5D&G%5BA%5D

Let's begin by assuming N%5BA%5D=T.

If N%5BA%5D=T then N%5BB%5D=T, but if N%5BB%5D=T then N%5BA%5D=F. This is a contradiction. Therefore N%5BA%5D=F

N%5BA%5D=F => nN%5BB%5D v nG%5BA%5D

nG%5BA%5D => G%5BB%5D. Let's save this result for later.

nN%5BB%5D => N%5BA%5D (not not N%5BA%5D) v nG%5BA%5D

We have already proven N%5BA%5D=F, so for nN%5BB%5D to be true, nG%5BA%5D must be true, and, again, nG%5BA%5D => G%5BB%5D.

Therefore, the gold is in Box B.