SOLUTION: I ahve a worksheet that I am having trouble with. It says: Find the equation of the line in the graph. On the graph it gives the point (0,3). The sine drawn seems to cross the x

Algebra ->  Graphs -> SOLUTION: I ahve a worksheet that I am having trouble with. It says: Find the equation of the line in the graph. On the graph it gives the point (0,3). The sine drawn seems to cross the x      Log On


   

Question 129779This question is from textbook algebra concepts and applications
: I ahve a worksheet that I am having trouble with. It says:
Find the equation of the line in the graph. On the graph it gives the point (0,3). The sine drawn seems to cross the x-axis at (-3,0).
I am totally stumped. Can you please help?
Thanks This question is from textbook algebra concepts and applications

Found 2 solutions by checkley71, solver91311:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
(Y2-Y1)/(X2-X1)
(0-3)/(-3-0)
-3/-3=1 IS THE SLOPE.
NOW USING THE LINE EQUATION Y=mX+b & A SET OF (X,Y) VALUES WE SOLVE FOR THE Y INTERCEPT(b).
3=1*0+b
b=3 THE Y INTERCEPT.
THUS THE EQUATION OF THIS LINE IS:
Y=X+3

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
Well, if you are sure about that second point, you can use the two-point form of the line:

y-y%5B1%5D=%28%28y%5B1%5D-y%5B2%5D%29%2F%28x%5B1%5D-x%5B2%5D%29%29%28x-x%5B1%5D%29

Lets say that P%5B1%5D is (0,3) and P%5B2%5D is (-3,0). (It doesn't matter which point you call 1 and which you call 2 as long as you keep it consistent.) That means that:

x%5B1%5D=0,
y%5B1%5D=3,
x%5B2%5D=-3, and
y%5B2%5D=0.

Just plug in the numbers and do the arithmetic:
y-3=%28%283-0%29%2F%280-%28-3%29%29%29%28x-0%29

y-3=%283%2F3%29%28x%29

y-3=x

y=x%2B3



If the graph you are working with looks like this, then we have it pretty close anyway.