SOLUTION: The sum of the squares of two consecutive even integers is 100. Find the two integers.

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Question 129499This question is from textbook
: The sum of the squares of two consecutive even integers is 100. Find the two integers. This question is from textbook

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X^2+(X+2)^2=100
X^2+X^2+4X+4=100
2X^2+4X+4-100=0
2X^2+4X-96=0
2(X^2+2X-48)=0
2(X+8)(X-6)=0
X-6=0
X=6 FOR THE FIRST EVEN INTEGER.
6+2=8 FOR THE OTHER INMTEGER.
PROOF:
6^2+8^2=100
36+64=100
100=100