SOLUTION: I am really stuck on this math homework problem i got the rest but not this one. How do you graph this equation by using the slope and a point on the line. this is the question y-2

Algebra ->  Graphs -> SOLUTION: I am really stuck on this math homework problem i got the rest but not this one. How do you graph this equation by using the slope and a point on the line. this is the question y-2      Log On


   

Question 129494: I am really stuck on this math homework problem i got the rest but not this one. How do you graph this equation by using the slope and a point on the line. this is the question y-2=3(x-5)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
y-5=3%28x-2%29 Start with the given equation


y-5=3x%2B%283%29%28-2%29 Distribute 3

y-5=3x-6 Multiply 3 and -2 to get -6

y=3x-6%2B5 Add 5 to both sides to isolate y

y=3x-1 Combine like terms -6 and 5 to get -1

Now let's graph y=3x-1





Looking at y=3x-1 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=3 and the y-intercept is b=-1


Since b=-1 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 3, this means:

rise%2Frun=3%2F1


which shows us that the rise is 3 and the run is 1. This means that to go from point to point, we can go up 3 and over 1



So starting at , go up 3 units


and to the right 1 unit to get to the next point



Now draw a line through these points to graph y=3x-1

So this is the graph of y=3x-1 through the points and