SOLUTION: Mike invested $6000 for one year. He invested part of it at 9% and the rest at 11%. At the end of the year he earned $624 in interest. How much did he invest at each rate?

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Question 129391This question is from textbook A Survey of Mathematics with Applications
: Mike invested $6000 for one year. He invested part of it at 9% and the rest at 11%. At the end of the year he earned $624 in interest. How much did he invest at each rate? This question is from textbook A Survey of Mathematics with Applications

Answer by amine(11) About Me  (Show Source):
You can put this solution on YOUR website!
we suppose that X is the value invisted by 9%
then 9%X+11%(6000-X)=624 => 9X-11X+66000=62400 => X=1800 the value invested at 9% and Y=6000-1800=4200 is the value invested at 11%