Question 129363: Please help me solve for x:
a) logbase12(x^2-x)=1
b) (logbase2 x)^2-6*(logbase2 x) +8=0
c) (logbase3 x)^2-4*(logbase3 x) +3=0 Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! log[12](x^2-x)=1
12^(log[12](x^2-x))=12^1
x^2-x=12
x^2-x-12=0
(x-4)(x+3)=0
x=4, x=-3
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(log[2]x)^2-6(log[2]x+8=0
(log[2]x-4)(log[2]x-2)=0
log[2]x=4
2^log[2]x=2^4
x=16
log[2]x=2
2^log[2]x=2^2
x=4
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c is similar to b.
I'll let you do that one.
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Ed
