SOLUTION: A worker can finish a job in 18 days.An other worker can do the same work but in 24 days and an other worker can do the same work in 30 days . If the 3 workers work 6 days together
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: A worker can finish a job in 18 days.An other worker can do the same work but in 24 days and an other worker can do the same work in 30 days . If the 3 workers work 6 days together
Log On
Question 128983: A worker can finish a job in 18 days.An other worker can do the same work but in 24 days and an other worker can do the same work in 30 days . If the 3 workers work 6 days together,what part of the job will be done ??
You can put this solution on YOUR website!
Let x=part of job that will be done with all three working together for 6 days
Worker #1 works at the rate of 1/18 of the job per day or 6/18 of the job in 6 days
Worker #2 works at the rate of 1/24 of the job per day or 6/24 of the job in 6 days
Worker #3 works at the rate of 1/30 of the job per day or 6/30 of the job in 6 days
So together they do:
6/18+6/24+6/30 of the job in 6 days and this equals:
1/3+1/4+1/5 =20/60+15/60+12/60 =x=
47/60 of the job in 6 days
