SOLUTION: Two students have 920$ altogether. How much does each have if 5/7 of the money of the first one is equal to 3/5 of the money of the second student?
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-> SOLUTION: Two students have 920$ altogether. How much does each have if 5/7 of the money of the first one is equal to 3/5 of the money of the second student?
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Question 128912: Two students have 920$ altogether. How much does each have if 5/7 of the money of the first one is equal to 3/5 of the money of the second student?
Please help !! Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! (5/7)X=(3/5)(920-X)
5X/7=(2760-3X)/5 CROSS MULTIPLY.
5*5X=7(2760-3X)
25X=19320-21X
25X+21X=19320
46X=19320
X=19320/46
X=420 ANSWER FOR THE AMOUNT FOR THE FIRST STUDENT.
920-420=500 FOR THE SECOND STUDENT.
PROOF:
5*420/7=3*500/5
2100/7=1500/5
300=300
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