SOLUTION: I am struggling with the concept of finding the missing coordinates on the ordered-pair linear equation. I have sat at my computer for many hours(no joke) on the same few problems.

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Question 128659This question is from textbook beginning algebra
: I am struggling with the concept of finding the missing coordinates on the ordered-pair linear equation. I have sat at my computer for many hours(no joke) on the same few problems. I will be submitting 4... but 1 per/submission.
OK here is the equation
(((2y+3x=11))) a.(-2,?) b.(?,3)
I know the -2 is for x sub1 and the 3 is y sub2 but I am very lost using the y=mx+b formula. Please help me step by step on how to solve for the missing coordinates. I am grateful for your time. Thank you in advance. This question is from textbook beginning algebra

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
The following is the answer posted for a very similar problem earlier this evening, but there should be enough here to guide you to a solution.

2x%2B%281%2F5%29y=6

Look at your equation as a rule for describing a set of points that lie in a straight line -- hence the term, 'linear' equation. By writing the equation, you have created a relationship between the equation and that set of points such that if you substitute the x- and y-coordinate values from any point that IS on the line back into the equation, you will get a true statement. On the other hand, if you substitute the x- and y-coordinates from a point that IS NOT on the line, you will get a false statement.

Let's use a simple example to illustrate the concept. We'll use y=2x. The point (1,2) lies on the line, and we know this for sure because if we substitute the number 1 for x and the number 2 for y in the equation, we get 2=2%281%29 or just 2=2 which we know to be a true statement. But let's look at the point (5,1). If we substitute the x-coordinate, 5, and the y-coordinate, 1 into the equation we get 1=2%285%29 or 1+=+10, clearly a false statement. So we can say with certainty that the point (5,1) does not lie on the line.

For your problem, you are faced with having to determine, for part a, what value of x will make the equation 2x%2B1%2F5y=6 true whenever y has the value 20. So let's put 20 into the equation and see what happens:

2x%2B%281%2F5%29%2820%29=6

2x+%2B+4+=+6

2x+=+2

x=1

You should be able to tackle part b by yourself now. Write back if you are still stuck.