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Question 128607: Part A) solve 5x+6y=18 for y
Part B) When graphed this equation would be a line. By examining your answer to part A, what is the slope and y-intercept of this line?
Part C) Using your answer from part A, find the corresponding value of y when x = 12
Found 2 solutions by checkley71, bucky:
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! PART A)
5X+6Y=18
6Y=-5X+18
Y=-5X/6+18/6
Y=-5X/6+3 ANSWER FOR THE LINE EQUATION & THE VALUE OF Y.
PART B)
Y=mX+b
WHERE m=SLOPE & b=Y INTERCEPT.
THE SLOPE=-5/6 & THE Y INTERCEPT=3.
PART C)
Y=-5*12/6+3
Y=-5*2+3
Y=-10+3
Y=-7 ANSWER.
Answer by bucky(2189) (Show Source):
You can put this solution on YOUR website! Given:
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To solve this equation for y, begin by getting rid of the 5x term on the left side by subtracting
5x from both sides. When you subtract 5x from both sides the result is:
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Next, divide both sides (all terms) by 6 (because 6 is the multiplier of the y) and the equation
then becomes:
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And recognize on the right side that  and this makes the equation become:
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This is the answer to the first part of the problem.
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This answer is in the form:
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in which m and b are constants. This form of a linear equation is the slope intercept form
because m, the multiplier, is the slope of the equation, and b, the constant, is the y-intercept
... or the value on the y-axis where the graph crosses the y-axis. So, you can just look at
your answer for the first part of the problem and by inspection tell that the graph has
a slope of  because that is the multiplier of the x. And you can tell that the
graph intercepts or crosses the y-axis where y equals +3 because that is the constant in
your answer.
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For Part C of your problem, just take your answer for the first part, substitute 12 for x
and simplify the answer as follows:
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Start with the answer to the first part:
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Substitute 12 for x to get:
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Multiply the first term on the right side.  and the problem
simplifies to:
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So the answer to Part C is 
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Hope this helps you to understand the problem and how each answer can be found.
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