SOLUTION: Felix has 40 coins consisting of dimes and nickels. If the value of his coins is $3.80, then how many of each type does he have?

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Question 128502: Felix has 40 coins consisting of dimes and nickels. If the value of his coins is $3.80, then how many of each type does he have?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
d = number of dimes
n = number of nickels
n+%2B+d+=+40
d+=+40+-+n
5n+%2B+10d+=+380
5n+%2B+10%2840+-+n%29+=+380
5n+%2B+400+-+10n+=+380
-5n+=+-20
n+=+4
d+=+40+-+n
d+=+36
He has 4 nickels and 36 dimes
check answer:
5n+%2B+10d+=+380
5%2A4+%2B+10%2A36+=+380
20+%2B+360+=+380
380+=+380
OK