SOLUTION: {{{x^3-5x^2+8x-4=0}}}

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Question 128285: x%5E3-5x%5E2%2B8x-4=0
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
x^3-5x^2+8x-4=0
1 is a root (sum of coefficients is 0)
doing the division by x-1
1 -5 8 -4
1 1 -4 4
1 -4 4 0
then
x^2-4x+4=0 then (x-2)^2=0 then roots are
1 and 2(multiplicity 2)