SOLUTION: Solve the problem: One number is 6 less than a second number. Twice the second number is 48 more than 5 times the first. Find the two numbers

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Question 128265:
Solve the problem: One number is 6 less than a second number. Twice
the second number is 48 more than 5 times the first. Find the two
numbers
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X=Y-6
2Y=5X+48
2Y=5(Y-6)+48
2Y=5Y-30+48
2Y-5Y=18
-3Y=18
Y=18/-3
Y=-6 ANSWER.
X=-6-6
X=-12 ANSWER.
PROOF:
2*-6=5*-12+48
-12=-60+48
-12=-12