Question 128198: Sketch the graph of f(x) = x^2-6x +8. Label all x-intercept, y-intercepts
and the vertex.
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Start with the given function
To find the x-intercept, let
Plug in
Factor the right side (note: if you need help with factoring, check out this solver)
Now set each factor equal to zero:
or
or Now solve for x in each case
So the x-intercepts are (2,0) and (4,0)
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To find the y-intercept, plug in
Start with the given function
Plug in
Raise 0 to the 2nd power to get 0
Multiply 1 and 0 to get 0
Multiply 6 and 0 to get 0
Subtract 0 from 0 to get 0
Add 0 and 8 to get 8
So when , we have
So this means that the y-intercept is (0,8)
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To find the vertex, we first need to find the axis of symmetry (ie the x-coordinate of the vertex)
To find the axis of symmetry, use this formula:
From the equation we can see that a=1 and b=-6
Plug in b=-6 and a=1
Negate -6 to get 6
Multiply 2 and 1 to get 2
Reduce
So the axis of symmetry is
So the x-coordinate of the vertex is . Lets plug this into the equation to find the y-coordinate of the vertex.
Lets evaluate
Start with the given polynomial
Plug in
Raise 3 to the second power to get 9
Multiply 6 by 3 to get 18
Now combine like terms
So the vertex is (3,-1)
So putting all of this together, we get
Graph of
and we can see that the x-intercepts are (2,0) and (4,0), the graph has the y-intercept (0,8), and the vertex is (3,-1). So this visually verifies our answer.
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