Question 128198:  Sketch the graph of f(x) = x^2-6x +8. Label all x-intercept, y-intercepts  
and the vertex. 
 Answer by jim_thompson5910(35256)      (Show Source): 
You can  put this solution on YOUR website!   Start with the given function
 
 
 
To find the x-intercept, let  
 
 
  Plug in  
 
 
 
 
  Factor the right side (note: if you need help with factoring, check out this solver)
 
 
 
 
Now set each factor equal to zero:
 
  or    
 
 
  or       Now solve for x in each case
 
 
 
 
So the x-intercepts are (2,0) and (4,0)
 
 
 
 
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To find the y-intercept, plug in  
 
 
 
  Start with the given function
 
 
 
  Plug in  
 
 
 
  Raise 0 to the 2nd power to get 0
 
 
 
  Multiply 1 and 0 to get 0
 
 
 
  Multiply 6 and 0 to get 0
 
 
 
  Subtract 0 from 0 to get 0
 
 
 
  Add 0 and 8 to get 8
 
 
 
So when  , we have  
 
 
 
 
So this means that the y-intercept is (0,8)
 
 
 
 
 
 
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To find the vertex, we first need to find the axis of symmetry (ie the x-coordinate of the vertex)
 
To find the axis of symmetry, use this formula:
 
 
 
 
 
From the equation   we can see that a=1 and b=-6
 
 
  Plug in b=-6 and a=1
 
 
 
  Negate -6 to get 6
 
 
 
  Multiply 2 and 1 to get 2
 
 
 
 
  Reduce
 
 
 
So the axis of symmetry is   
 
 
 
So the x-coordinate of the vertex is  . Lets plug this into the equation to find the y-coordinate of the vertex.
 
 
 
Lets evaluate  
 
 
  Start with the given polynomial
 
 
 
  Plug in  
 
 
 
  Raise 3 to the second power to get 9
 
 
 
  Multiply 6 by 3 to get 18
 
 
 
  Now combine like terms
 
 
 
So the vertex is (3,-1)
 
 
 
 
 
So putting all of this together, we get
 
 
 
  Graph of   
 
 
 
and we can see that the x-intercepts are (2,0) and (4,0), the graph has the y-intercept (0,8), and the vertex is (3,-1). So this visually verifies our answer. 
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