SOLUTION: find two positive numbers whoes ratio is 8 to 3 and whose product is 864

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Question 128191: find two positive numbers whoes ratio is 8 to 3 and whose product is 864
Answer by marcsam823(57) About Me  (Show Source):
You can put this solution on YOUR website!
We are given two conditions:
Let x = the first number
Let y = the second number
We are given two conditions:
The first is the numbers have a ratio of 8 to 3 or 8%2F3
Therefore x%2Fy+=+8%2F3
Another way to write this would be:
x+=+8y%2F3
The second condition is that they multiply to 864, so:
x%2Ay+=+864
Substitute for x in the second equation:
%288y%2F3%29%2Ay+=+864
Solve for y:
8y%5E2%2F3+=+864
8y%5E2+=+2592
y%5E2+=+324
y = +/-18 (reject the negative answer because the problem asks for two positive numbers)
y+=+18
Solve for x by substituting:
x%2Ay+=+864
x%2A18+=+864
x+=+48
Check:
x+=+8y%2F3
48+=+8%2818%29%2F3
48+=+144%2F3
48+=+48
The two numbers are 18 and 48