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Question 128027This question is from textbook algebra: structure and method: book1
: I am supposed to write an equation in standard form of the line passing through these points. (-2,0) and (2,-3). PLEASE HELP!!!!!! The answer is 3x+4y=-6, but I don't know how to get there. HELP MUCH APPRECIATED!!!!
This question is from textbook algebra: structure and method: book1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! write an equation in standard form of the line passing through these points.
(-2,0) and (2,-3)
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slope = (-3-0)/(2--2) = -3/4
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Form of the equation: y = mx + b
You now know x,y, and m; solve for b as follows:
-3 = (-3/4)*2+b
-3 = (-3/2) + b
b = (-3/2)
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EQUATION:
y = (-3/4)x - (3/2)
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Write it in standard form:
Multiply thru by 4 to get:
4y = -3x - 6
Rearrange:
3x+4y = -6
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Cheers,
Stan H.
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