Lets start with the given system of linear equations 
   
    
    
   
  In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa). 
   
  So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero. 
   
  So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 4 and 5 to some equal number, we could try to get them to the LCM. 
   
  Since the LCM of 4 and 5 is 20, we need to multiply both sides of the top equation by 5 and multiply both sides of the bottom equation by -4 like this: 
   
    Multiply the top equation (both sides) by 5 
    Multiply the bottom equation (both sides) by -4 
   
   
  So after multiplying we get this: 
    
    
   
  Notice how 20 and -20 add to zero (ie  ) 
   
   
  Now add the equations together. In order to add 2 equations, group like terms and combine them 
    
   
    
   
    Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether. 
   
   
   
  So after adding and canceling out the x terms we're left with: 
   
    
   
    Divide both sides by   to solve for y 
   
   
   
    Reduce 
   
   
  Now plug this answer into the top equation   to solve for x 
   
    Plug in   
   
   
    Multiply 
   
   
   
    Reduce 
   
   
   
    Subtract   from both sides 
   
    Make 22 into a fraction with a denominator of 31 
   
    Combine the terms on the right side 
   
    Multiply both sides by  . This will cancel out   on the left side. 
   
   
    Multiply the terms on the right side 
   
   
  So our answer is  
   
   ,    
   
  which also looks like 
   
  ( ,  ) 
   
  Notice if we graph the equations (if you need help with graphing, check out this solver) 
   
    
    
   
  we get  
   
   
   
    graph of   (red)   (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle). 
   
   
  and we can see that the two equations intersect at ( , ). This verifies our answer. |