SOLUTION: 1.On a road in the city of Rochester, the maximum speed is 50 miles per hour, and the minimum speed is 20 miles per hour. Which compound inequality represents the situation. a. 2

Algebra ->  Inequalities -> SOLUTION: 1.On a road in the city of Rochester, the maximum speed is 50 miles per hour, and the minimum speed is 20 miles per hour. Which compound inequality represents the situation. a. 2      Log On


   



Question 127769: 1.On a road in the city of Rochester, the maximum speed is 50 miles per hour, and the minimum speed is 20 miles per hour. Which compound inequality represents the situation.
a. 20>x>50
b. 20 c. 20<=x<=50
d. 20>=x>=50
2. Write an inequality for the situation:
All real numbers y that are less than 4 or greater than 9.
3. Solve the inequality:
a+8-2(a-12)>0
PLEASE HELP!!!!

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If the minimum speed is 20 mph, then you must go 20 mph or faster. So mathematically, this looks like x%3E=20. Also, if the maximum speed is 50 mph, then the upper limit is 50. So mathematically, this looks like x%3C=50.


So we have these two inequalities

x%3E=20 and x%3C=50

Rearrange x%3E=20 to get 20%3C=x


Now we can combine 20%3C=x and x%3C=50 to get 20%3C=x%3C=50


So our answer is C




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# 2

The statement "that are less than 4" translates to y%3C4 and the statement "greater than 9" translates to y%3E9


So together we have


y%3C4 or y%3E9


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# 3



a%2B8-2%28a-12%29%3E0 Start with the given inequality



a%2B8-2a%2B24%3E0 Distribute


-a%2B32%3E0 Combine like terms on the left side


-a%3E0-32Subtract 32 from both sides


-a%3E-32 Combine like terms on the right side


a%3C%28-32%29%2F%28-1%29 Divide both sides by -1 to isolate a (note: Remember, dividing both sides by a negative number flips the inequality sign)



a%3C32 Divide

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Answer:
So our answer is a%3C32