SOLUTION: Hey i need help in this problem i did it but i don't know if its right or not here it is. These are the steps for both of the problems a) Rewrite in slope-intercform b) id

Algebra ->  Graphs -> SOLUTION: Hey i need help in this problem i did it but i don't know if its right or not here it is. These are the steps for both of the problems a) Rewrite in slope-intercform b) id      Log On


   

Question 127399: Hey i need help in this problem i did it but i don't know if its right or not
here it is.
These are the steps for both of the problems
a) Rewrite in slope-intercform
b) identify x-and y-intercepts
c)graph the equation
AND THESE ARE BOTH OF THE PROBLEMS
1) 5x-2y=5
2) 3x+5y=15
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do the first one to get you on track


# 1

a)



5x-2y=5 Start with the given equation


-2y=5-5x Subtract 5+x from both sides


-2y=-5x%2B5 Rearrange the equation


y=%28-5x%2B5%29%2F%28-2%29 Divide both sides by -2


y=%28-5%2F-2%29x%2B%285%29%2F%28-2%29 Break up the fraction


y=%285%2F2%29x-5%2F2 Reduce



So the equation is now in slope-intercept form (y=mx%2Bb) where the slope is m=5%2F2 and the y-intercept is b=-5%2F2






b)



5%2Ax-2%2Ay=5 Start with the equation in standard form

Let's find the x-intercept

To find the x-intercept, let y=0 and solve for x:
5%2Ax-2%2A%280%29=5 Plug in y=0

5%2Ax=5 Simplify

x=5%2F5 Divide both sides by 5


x=1 Reduce



So the x-intercept is (note: the x-intercept will always have a y-coordinate equal to zero)



------------------

5%2Ax-2%2Ay=5 Start with the equation in standard form

Now let's find the y-intercept

To find the y-intercept, let x=0 and solve for y:
5%2A%280%29-2%2Ay=5 Plug in x=0

2%2Ay=5 Simplify

x=5%2F-2 Divide both sides by -2



y=-5%2F2 Reduce



So the y-intercept is (note: the y-intercept will always have a x-coordinate equal to zero)

------------------------------------------

So we have these intercepts:
x-intercept:

y-intercept:







c)

Now let's use the equation y=%285%2F2%29x-5%2F2 to graph




Looking at y=%285%2F2%29x-5%2F2 we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=5%2F2 and the y-intercept is b=-5%2F2


Since b=-5%2F2 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis

So we have one point note: the point also looks like (0,-2.5)




Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun

Also, because the slope is 5%2F2, this means:

rise%2Frun=5%2F2


which shows us that the rise is 5 and the run is 2. This means that to go from point to point, we can go up 5 and over 2



So starting at , go up 5 units


and to the right 2 units to get to the next point



Now draw a line through these points to graph y=%285%2F2%29x-5%2F2

So this is the graph of y=%285%2F2%29x-5%2F2 through the points and