SOLUTION: the mansfield tigers were playing the cougars on Friday Fight. Tickets wnet on sale at four o'clock on Thursday afternoon. Adult tickets sold for five dollars and student tickets c
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-> SOLUTION: the mansfield tigers were playing the cougars on Friday Fight. Tickets wnet on sale at four o'clock on Thursday afternoon. Adult tickets sold for five dollars and student tickets c
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Question 127392: the mansfield tigers were playing the cougars on Friday Fight. Tickets wnet on sale at four o'clock on Thursday afternoon. Adult tickets sold for five dollars and student tickets cost 3.50. The total proceeds from Thursday's ticket sales were 155. if 37 tickets were sold on Thursday, how many were adult tickets and how many were adult tickets and how many were student tickets? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Adult tickets sold for five dollars and student tickets cost 3.50. The total proceeds from Thursday's ticket sales were 155. if 37 tickets were sold on Thursday, how many were adult tickets and how many were adult tickets and how many were student tickets?
:
Let a = no. of adult tickets
Let s = no. of student tickets
:
The ticket value$ equation:
5a + 3.5s = 155
;
The total tickets sold equation:
a + s = 37
we can also write it as:
s = (37 - a)
:
Substitute (37-a) for s in the 1st equation:
5a + 3.5(37-a) = 155
:
5a + 129.5 - 3.5a = 155; multiplied what's inside the brackets.
:
5a - 3.5a = 155 - 129.5
:
1.5a = 25.5
a =
a = 17 adult tickets sold
then
37 - 17 = 20 student tickets sold
;
:
Check solution in the $$ equation:
5(17) + 3.5(20) =
85 + 70 = 155; confirms our solutions
:
Did this make sense to you? Any questions?
