SOLUTION: A man has twenty coins consisting of dimes and quarters. If the dimes were quarters and the quarters were dimes, he would have ninety cents more than he has now. How many dimes and

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Question 127310This question is from textbook Introductory and Intermediate Algebra
: A man has twenty coins consisting of dimes and quarters. If the dimes were quarters and the quarters were dimes, he would have ninety cents more than he has now. How many dimes and quarters does he have? This question is from textbook Introductory and Intermediate Algebra

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let d = actual number of dimes
Let q = actual number of quatrers
d+%2B+q+=+20
The amount of money he actually has is 10d+%2B+25q
The problem says 25d+%2B+10q+=+10d+%2B+25q+%2B+90
25d+-+10d+-+25q+%2B+10q+=+90
15d+-+15q+=+90
15%28d+-+q%29+=+90
d+-+q+=+6
d+=+q+%2B+6
and from above
d+%2B+q+=+20
q+%2B+6+%2B+q+=+20
2q+=+14
q+=+7
d+=+q+%2B+6
d+=+7+%2B+6
d+=+13
He has 13 dimes and 7 quarters
check:
15%28d+-+q%29+=+90
15%2813+-+7%29+=+90
15%2A6+=+90
90+=+90
OK