SOLUTION: The roots of the equation 2x^2-5=0 are 1) imaginary 2) real, rational, and equal 3) real, rational, and unequal 4) real and irrational

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The roots of the equation 2x^2-5=0 are 1) imaginary 2) real, rational, and equal 3) real, rational, and unequal 4) real and irrational      Log On


   

Question 127196: The roots of the equation 2x^2-5=0 are
1) imaginary 2) real, rational, and equal 3) real, rational, and unequal
4) real and irrational
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2-5=0
2x^2=5
x^2=5/2
x=+-sqrt(5/2)
The sqrt of a positive rational number that is not a perfect square is a real, irrational number.
.
Ed