Question 127157: the frequency(F) of vibration of a string varies directly as the square root of the tension(t) and inversely as the length(L) and diameter(d). if a string of 5 cm long, with a diameter of 0,05 cm vibrates at a frequency of 1300 v/s at a voltage of 16 kg, what will be the frequency of a rope 15 inches long and 0,08 cm in diameter at a voltage of 25 kg?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! the frequency(F) of vibration of a string varies directly as the square root of the tension(t) and inversely as the length(L) and diameter(d). if a string of 5 cm long, with a diameter of 0,05 cm vibrates at a frequency of 1300 v/s at a voltage of 16 kg, what will be the frequency of a rope 15 inches long and 0,08 cm in diameter at a voltage of 25 kg?
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F=k*sqrt(t)/Ld
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Need to find "k"
1300 = k*sqrt(16)/(5*0.05)
1300 = k*(1/4)
k = 5200
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Equation to use in the next part:
F = 5200*sqrt(t)/(Ld)
F = 5200*sqrt(25)/(15 inches*0.08 cm)
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Comment: Did you mean to have a rope with length 15 inches or should
that be 15 cm?
You need to have the length and the diameter measured in cm's.
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Cheers,
stan H.
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