SOLUTION: I can only get so far on this division question then I am stuck. (4x^2â-xâ+5)/(2xâ+1). I know the first number in the quotient is 2xâ however, how do I divide xâ+5 (remainder), by

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I can only get so far on this division question then I am stuck. (4x^2â-xâ+5)/(2xâ+1). I know the first number in the quotient is 2xâ however, how do I divide xâ+5 (remainder), by      Log On


   

Question 127113: I can only get so far on this division question then I am stuck.
(4x^2â-xâ+5)/(2xâ+1). I know the first number in the quotient is 2xâ however, how do I divide xâ+5 (remainder), by the divisor 2xâ+1. The answer is 2xâ-3/2;R=13/2. How do I find the fractions to solve this one
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
There is some strange symbols in your expression I assume that you mean:
:
%284x%5E2+-+x+%2B+5%29%2F%282x%2B1%29
:
:
Using long division using "......" to keep thing lined up:
:
...........................2x - 3/2; (note that you have to multiply 2 by 3/2 to get 3)
.............------------------
2x + 1 | 4x^2 - x + 5
................4x^2 -2x
....................-------------
............................-3x + 5
............................-3x - 3/2
...............................--------
......................................+5 & 3/2 remainder which is 13/2
:
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