SOLUTION: The speed of train A is going 18 mph slower then the speed of train B. Train A travels 220 miles in the same time that it takes train B to travel 310 miles. Find the speed of each

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Question 127068This question is from textbook Introductory Algebra
: The speed of train A is going 18 mph slower then the speed of train B. Train A travels 220 miles in the same time that it takes train B to travel 310 miles. Find the speed of each train.
Train A-
Train B- This question is from textbook Introductory Algebra

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Say s= speed of train A
s+%2B+18 = speed of train B
t = time each one spends
train A- 220+=+s%2At
train B- 310+=+%28s+%2B+18%29%2At
solve each one for t
t+=+220%2Fs
t+=+310+%2F+%28s+%2B+18%29
220%2Fs+=+310+%2F+%28s+%2B+18%29
multiply each side by s%2A%28s+%2B+18%29
220%28s+%2B+18%29+=+310s
220s+%2B+3960+=+310s
90s+=+3960
s+=+44
s+%2B+18+=+62
train A is going 44 mi/hr
train B is going 62 mi/hr
check:
220%2Fs+=+310+%2F+%28s+%2B+18%29
220%2F44+=+310+%2F+%2844+%2B+18%29
5+=+5
OK