SOLUTION:
Janet invested $31,000, part at 10% and part at 1%. If the total interest at the end of the year is $1,390, how much did she invest at 10%?
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Janet invested $31,000, part at 10% and part at 1%. If the total interest at the end of the year is $1,390, how much did she invest at 10%?
please help
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Question 127046:
Janet invested $31,000, part at 10% and part at 1%. If the total interest at the end of the year is $1,390, how much did she invest at 10%?
please help Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! .10x+.01(31,000-x)=1390
.10x+310-.01x=1390
.09x=1390-310
.09x=1080
x=1080/.09
x=12,000 answer for the amount invested @ 10%.
31,000-12,000=19,000 amount invested @ 1%.
PROOF:
.10*12000+.01*19000=1390
1200+190=1390
1390=1390
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