SOLUTION: A STUDENT WITH A 1.875 GPA HAS 24 CREDIT HOURS. FIND HOW MANY CREDIT HOURS OF B's (AT 3 POINTS PER CREDIT HOUR) HE WILL NEED TO RAISE HIS GPA TO A 2.40.

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Question 126904: A STUDENT WITH A 1.875 GPA HAS 24 CREDIT HOURS. FIND HOW MANY CREDIT HOURS OF B's (AT 3 POINTS PER CREDIT HOUR) HE WILL NEED TO RAISE HIS GPA TO A 2.40.
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A STUDENT WITH A 1.875 GPA HAS 24 CREDIT HOURS. FIND HOW MANY CREDIT HOURS OF B's (AT 3 POINTS PER CREDIT HOUR) HE WILL NEED TO RAISE HIS GPA TO A 2.40.
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Let "x" be the number of B-credit hours he needs.
EQUATION:
(24*1.875+3x)/(24+x)=2.40
(45+3x)=57.6+2.4x
12.6 = 0.6x
x = 21
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Cheers,
Stan H.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
A student already has 24 credits hours……….=> 8grades
And has a 1.875+GPA………. which is equal to total number of points (which is 45)
divided by number of earned credits hours ( which is 24)
B%27s gives you GPA of 3.00
To raise his GPA to a2.40, student needs x+ B's

2.40=+%2845%2B3%2Ax%29%2F%2824%2Bx%29+…..note, student will have only B's (no A’s, no C’s, D’s, or F’s)
solve for x
%282.40%29%2824%2Bx%29+=+45+%2B+3%2Ax…..

57.6+%2B+2.40x+=+45+%2B+3x…..
57.6+-45+=+3x+-2.40+x+…..

57.6+-45+=+%283+-2.40%29+x+…..
12.6+=+0.6x+…..
x+=+21

Check:
2.40=+%2845%2B3%2A21%29%2F%2824%2B21%29+…..

2.40=+%2845%2B63%29%2F45…..
2.40=+108%2F45+…..
2.40=+2.4…..