SOLUTION: Three times the square of a certain positive number exceeds six times the number by nine. Find the number
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Question 126735
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Three times the square of a certain positive number exceeds six times the number by nine. Find the number
Answer by
checkley71(8403)
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3X^2=6X+9
3X^2-6X-9=0
3(X^2-2X-3)=0
3(X-3)(X+1)=0
X-3=0
X=3 ANSWER.
X+1=0
X=-1 ANSWER.PROOFS:
3*3^2=6*3+9
3*9=18+9
27=27
3*-1^2=6*-1+9
3*1=-6+9
3=3