SOLUTION: ONE ANGLE OF A TRIANGLE HAS A MEASURE THAT IS 10 MORE THAN TWICE THAT OF THE SECOND ANGLE. THE THIRD ANGLE HAS A MEASURE 10 LESS THAN THE FIRST. FIND THE MEASURE OF EACH ANGLE OF
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Question 126725: ONE ANGLE OF A TRIANGLE HAS A MEASURE THAT IS 10 MORE THAN TWICE THAT OF THE SECOND ANGLE. THE THIRD ANGLE HAS A MEASURE 10 LESS THAN THE FIRST. FIND THE MEASURE OF EACH ANGLE OF THE TRIANGLE. Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! 2x+10, x, (2x+10-10) are the three angles.
2x+10+x+2x+10-10=180
5x=180-10
5x=170
x=170/5
x=34 degrees for the second angle.
2*34+10=68+10=78 degrees for the first angle.
2*34+10-10=68 degrees for the third angle.
PROOF:
34+78+68=180
180=180
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