SOLUTION: A pharmasist needs 500 milliliters of a 20% phenobarbital solution. But has only 5% and 25% phenobarbital solutions available. Find how many milliliters of each he should mix to

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A pharmasist needs 500 milliliters of a 20% phenobarbital solution. But has only 5% and 25% phenobarbital solutions available. Find how many milliliters of each he should mix to       Log On


   



Question 126663: A pharmasist needs 500 milliliters of a 20% phenobarbital solution. But has only 5% and 25% phenobarbital solutions available. Find how many milliliters of each he should mix to get the desired solution.
Found 2 solutions by edjones, josmiceli:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be ml of 5% soln.
let 500-x be ml of 25% soln.
.
x*.05=.05x
(500-x)*.25=125-.25x
500*.20=100
.
.05x+125-.25x=100
-.2x=-25
x=-25/-.2
x=125 ml of 5% soln.
500-x=375 ml of 25% soln.
.
Check:
125*.05= 6.25
375*.25=93.75
---------------
========100
.
Ed

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
%28.25x+%2B+.05y%29+%2F+500+=+.2
x+%2B+y+=+500
y+=+500+-+x
%28.25x+%2B+.05%28500+-+x%29%29+%2F+500+=+.2
%28.25x+%2B+25+-+.05x%29+%2F+500+=+.2
%28.2x+%2B+25%29+%2F+500+=+.2
.2x+%2B+25+=+100
.2x+=+75
x+=+375
y+=+500+-+375
y+=+125
He needs 375 ml of the 25% solution and 125 ml of the 5% solution