SOLUTION: Jack usually mows his lawn in 4 hours. Marilyn can mow the same yard in 6 hours. How much time would it take for them to mow the lawn together?

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Question 126643: Jack usually mows his lawn in 4 hours. Marilyn can mow the same yard in 6 hours. How much time would it take for them to mow the lawn together?
Found 2 solutions by LarsJongste, slim522:
Answer by LarsJongste(2) About Me  (Show Source):
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So first i make fractions of the given numbers
Jack does 1/4 of a lawn in an hour
Marilyn does 1/6 of a lawn in an hour
if we go searching for a common numerator in those fractions you find
Jack 3/12 of a lawn in an hour
Marilyn 2/12 of a lawn in an hour
so their combined speed is
J&M 5/12 of a lawn in an hour (or you could say the do 5 lawn in 12 hours)

so the time taken for 1 lawn = 12 / 5 = 2.5 hours


Answer by slim522(1) About Me  (Show Source):
You can put this solution on YOUR website!
2 2/9 is the correct answer