SOLUTION: I have been struggling on this problem for a while now and I was wondering if anyone could help me? I would deeply appreciate it!! Please and Thank you!!
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Question 126636This question is from textbook Algebra Structure and Method
: I have been struggling on this problem for a while now and I was wondering if anyone could help me? I would deeply appreciate it!! Please and Thank you!!
Solving Problems Involving Inequalities
Solve.
A collection of quarter and dimes is worth more than $20. There are twice as many quarters as dimes. At least how many dimes are there? This question is from textbook Algebra Structure and Method
You can put this solution on YOUR website! A collection of quarter and dimes is worth more than $20. There are twice as many quarters as dimes. At least how many dimes are there?
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Write an equation for each statement: d = no. of dimes; q = no. of quarters
:
"A collection of quarter and dimes is worth more than $20."
.25q + .10d > 20.00
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" There are twice as many quarters as dimes."
q = 2d
:
At least how many dimes are there?
:
Substitute 2d for q in the 1st equation and find d:
.25(2d) .10d > 20
.5d + .1d > 20
.6d > 20
d >
d > 33.33 not possible so we can say At least 34 dimes
:
WE can check this, it means we have 68 quarters and 34 dimes
.25(68) + .10(34) = 20.40
if we had only 33 dimes
.25(66) + .10(33) = 19.80 less than 20
:
Did I make this understandable here?
