SOLUTION: Please help me solve this problem. Please give three significant digits.(I need to use logarithms also.) 2^x-2=14

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Please help me solve this problem. Please give three significant digits.(I need to use logarithms also.) 2^x-2=14      Log On


   



Question 126549: Please help me solve this problem. Please give three significant digits.(I need to use logarithms also.)
2^x-2=14

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
2^x - 2 = 14
:
Add 2 to both sides and you have:
2^x = 14 + 2
2^x = 16
Right here you can see that x = 4; x^4 = 16
:
However, if you insist on using logs:
ln(2^x) = ln(16)
:
Use the log equivalent of exponents
x*ln(2) = ln(16)
:
Find the nat logs
x * (.693147) = 2.772589
:
.693147x = 2.772589
:
x = 2.772589%2F.693147
x = 4.000
:
:
Check solution on a calc: enter: 2^4 - 2 = 14