SOLUTION: a quadrilateralhas four angle...each angle has a different measurment.. i have to figure out the value of x with the information below The measurement of angle A is (4x+10)degrees

Algebra ->  Polygons -> SOLUTION: a quadrilateralhas four angle...each angle has a different measurment.. i have to figure out the value of x with the information below The measurement of angle A is (4x+10)degrees      Log On


   

Question 126359: a quadrilateralhas four angle...each angle has a different measurment.. i have to figure out the value of x with the information below
The measurement of angle A is (4x+10)degrees
The measurement of angle B is 108 degrees
The measurement of angle C is 67 Degrees
The measurement of angle D is 3x dergrees

Help please!!!! i dont get it....thanx alot
Found 2 solutions by jim_thompson5910, checkley71:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Remember the sum of all four angles of any quadrilateral is always 360 degrees. So in other words, we have the equation:

A%2BB%2BC%2BD=360


4x%2B10%2B108%2B67%2B3x=360 Plug in A=4x%2B10, B=108, C=67 and D=3x




7x%2B185=360 Combine like terms on the left side


7x=360-185Subtract 185 from both sides


7x=175 Combine like terms on the right side


x=%28175%29%2F%287%29 Divide both sides by 7 to isolate x



x=25 Divide

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Answer:
So our answer is x=25


Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
4x+10+108+67+3x=360 or 7x=360-10-108-67 or 7x=175 or x=175/7 or x=25
4*25+10=100+10=110 for the first angle.
3*25=75 for the last angle.
PROOF: 110+108+67+75=360 or 360=360.