SOLUTION: A ball is thrown downward from a window in a tall building. Its position at time "t" in seconds is s = 16t^ + 32t, where "s" is in feet. How long (to the nearest tenth) will it
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Question 126358: A ball is thrown downward from a window in a tall building. Its position at time "t" in seconds is s = 16t^ + 32t, where "s" is in feet. How long (to the nearest tenth) will it take the ball to fall 137 feet?
in equation "16t^" means 16 t squared.
iF anyone could help that would be great!
thanks. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! s = 16t^ + 32t, where "s" is in feet. How long (to the nearest tenth) will it take the ball to fall 137 feet?
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s(t) = -16t^2s-32t+137
When the object hits the ground its height is zero
-16t^2-32t+137 = 0
t = [32 +- sqrt(32^2-4*-16*137)]/(-32)
t = [32 +- sqrt(9792)]/-32
t = [32 +- 98.954]/-32
Positive Answer
t = 2.0923..
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Cheers,
Stan H.
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