SOLUTION: | 2x - 7 | > 10 (problem) (my wrong answer) 2x-7>\(10) 2x-7>10 2x>17 x>(17)/(2) 2x-7<-(10) 2x-7<-10 2x<7-10 2x<-3 (2x)/(2)<-(3)/(2) x<-(3)/(2)

Algebra ->  Graphs -> SOLUTION: | 2x - 7 | > 10 (problem) (my wrong answer) 2x-7>\(10) 2x-7>10 2x>17 x>(17)/(2) 2x-7<-(10) 2x-7<-10 2x<7-10 2x<-3 (2x)/(2)<-(3)/(2) x<-(3)/(2)       Log On


   



Question 126224: | 2x - 7 | > 10 (problem)
(my wrong answer)
2x-7>\(10)
2x-7>10
2x>17
x>(17)/(2)
2x-7<-(10)
2x-7<-10
2x<7-10
2x<-3
(2x)/(2)<-(3)/(2)
x<-(3)/(2)
x>(17)/(2) or x<-(3)/(2) *needs interval notation do not forget*
problem:
| 4x + 2 | (greater than or equal to sign) 6

4x+2>=\(6)
4x+2>=6
4x>=4
x>=1
4x+2<=-(6)
4x+2<=-6
4x<=-2-6
4x<=-8
(4x)/(4)<=-(8)/(4)
x<=-(8)/(4)
x<=-2
x>=1 or x<=-2 *wrong needs interval notation do not forget*
what am I doing wrong??

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
|2x - 7 | > 10
2x-7 < -10 or 2x-7 > 10
2x < -3 or 2x > 17
x < -3/2 or x>17/2
Interval notation:
(-inf, -3/2)U(17/2, +inf)
======================
|4x + 2 | >= 6
4x+2 <= -6 or 4x+2 >= 6
4x <= -8 or 4x >=- 4
x <= -2 or x >=- -1
Interval notation:
(-inf, -2]U[-1, +inf)
========================
Cheers,
Stan H.