SOLUTION: find the slope, if it exists, of (-1,-2), (3,-2)

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Question 126066: find the slope, if it exists, of (-1,-2), (3,-2)
Found 2 solutions by jim_thompson5910, checkley71:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Let's denote the first point (-1,-2) as . In other words, and

Now let's denote the second point (3,-2) as . In other words, and



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m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula

m=%28-2--2%29%2F%283--1%29 Plug in y%5B2%5D=-2,y%5B1%5D=-2,x%5B2%5D=3,x%5B1%5D=-1


m=0%2F4 Subtract the terms in the numerator -2--2 to get 0. Subtract the terms in the denominator 3--1 to get 4

m=0 Reduce


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Answer:

So the slope of the line through the points (-1,-2) and (3,-2) is m=0

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
SLOPE=(Y2-Y1)/(X2-X1)=(-2+2)/(3+1)=0/4=0 THIS IS A HORIZONTAL LINE THROUGH THE POINT Y=-2.