SOLUTION:
The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 38 in., find the width of the rectangle.
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The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 38 in., find the width of the rectangle.
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Question 126021:
The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 38 in., find the width of the rectangle. Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! L=2W+10 THEN THE PERIMETER=2(2W+10)+2W
38=4W+20+2W OR 38-20=6W+2W OR 8W=18 OR W=18/8 OR W=2.25 IN.
PROOF
L=2*2.25+10) OR L=4.5+10 OR L=14.5
PROOF:
38=2*14.5+2*4.5 OR 38=29+9 OR 38=38
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