SOLUTION: Ms K is 6 years more than 3 times as old as her daughter. 8 years ago she was 2 years less than 9 times as old as her daughter was then. What are thier ages?
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Question 125965: Ms K is 6 years more than 3 times as old as her daughter. 8 years ago she was 2 years less than 9 times as old as her daughter was then. What are thier ages? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Let k = K's age now; let d = daughter's age now
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Just write an equation for what it says:
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"Ms K is 6 years more than 3 times as old as her daughter."
k = 3d + 6
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8 years ago they would have been
(k-8) and (d-8)
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"8 years ago she was 2 years less than 9 times as old as her daughter was then."
(k-8) = 9(d-8) - 2
:
k - 8 = 9d - 72 - 2
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k = 9d - 74 + 8
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k = 9d - 66
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What are their ages?
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Substitute (3d+6) for k in the above equation, find d
(3d+6) = 9d - 66
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3d - 9d = -66 - 6
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-6d = -72
d =
d = +12 yrs is the daughter's age now
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Mama would be: 36 + 6 = 42 yrs old now
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Check our solutions in the statement:
8 years ago she was 2 years less than 9 times as old as her daughter was then.
(42-8) = 9(12-8) - 2
34 = 9(4) - 2; confirms out solutions
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Could you follow this OK? Any questions?
