SOLUTION: How many ounces of a 50% acetic acid solution should a photgrapher add to 32 ounces of a 5% acetic acid solution to obtain a 10% acetic acid solution? Please help i do not know

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Question 125956: How many ounces of a 50% acetic acid solution should a photgrapher add to 32 ounces of a 5% acetic acid solution to obtain a 10% acetic acid solution?
Please help i do not know where to start with this problem.
Found 2 solutions by Earlsdon, ankor@dixie-net.com:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Start by assigning a variable to the unknown quantity.
Let x = the required number of ounces (oz) of the 50% acetic acid solution that must be added to the 32 oz of 5% acetic acid solution to obtain (32+x) oz of 10% acetic acid solution. After changing the percentages to their decimal equivalents, you can write the equation to solve for x.
0.5%28x%29%2B0.05%2832%29+=+%2832%2Bx%29%280.1%29 Simplify and solve for x.
0.5x+%2B+1.6+=+3.2+%2B+0.1x Subtract 0.1x from both sides.
0.4x%2B1.6+=+3.2 Subtract 1.6 from both sides.
0.4x+=+1.6 Finally, divide both sides by 0.4
x+=+4
You will need to add 4 oz of the 50% acetic acid soltion to the 32 oz of 5% acetic acid solution to obtain 36 (32+4) oz of the 10% acetic acid solution.
Check:
0.5x%2B0.05%2832%29+=+%2832%2Bx%29%280.1%29 Substitute x = 4.
0.5%284%29%2B1.6+=+%2832%2B4%29%280.1%29
2%2B1.6+=+36%280.1%29
3.6+=+3.6

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
How many ounces of a 50% acetic acid solution should a photographer add to 32 ounces of a 5% acetic acid solution to obtain a 10% acetic acid solution?
:
Let x = amt of acetic acid required
:
Since this is to be added to 32 oz, the final amt will be (x+32)
:
Write a decimal equation:
.50x + .05(32) = .10(x+32)
:
.5x + 1.6 = .1x + 3.2
:
.5x - .1x = 3.2 - 1.6
:
.4x = 1.6
x = 1.6%2F.4
x = 4 oz of 50% acetic acid required
:
:
Check solution in original equation:
.5(4) + .05(32) = .10(4+32)
2 + 1.6 = .1(36)
3.6 = 3.6; confirms our solution
:
Could you follow this OK? Did it make sense to you? Any questions?