SOLUTION: It gave me this information. y=x^2 , squareroot y= squareroot x^2, squareroot y=|x|
where therefore since x<equal 0, then -x=squareroot y and x=-sqrooty
The question is |x-3|>|2x
Algebra ->
Absolute-value
-> SOLUTION: It gave me this information. y=x^2 , squareroot y= squareroot x^2, squareroot y=|x|
where therefore since x<equal 0, then -x=squareroot y and x=-sqrooty
The question is |x-3|>|2x
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Question 125901: It gave me this information. y=x^2 , squareroot y= squareroot x^2, squareroot y=|x|
where therefore since x
The question is |x-3|>|2x+1|
I don't know how to solve this inequalitie. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! |x-3|>|2x+1|
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I graphed the left side and the right side on the same x/y axis and
found the solution set:
-4 < x < 2/3
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Cheers,
Stan H.
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