SOLUTION: Can you help me with this question? I came up with 15*0.05x=71 but this is not working out.
A promotional deal for long distance phone service charges a $15 basic fee plus $0.05 p
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: Can you help me with this question? I came up with 15*0.05x=71 but this is not working out.
A promotional deal for long distance phone service charges a $15 basic fee plus $0.05 p
Log On
Question 125846This question is from textbook
: Can you help me with this question? I came up with 15*0.05x=71 but this is not working out.
A promotional deal for long distance phone service charges a $15 basic fee plus $0.05 per minute for all calls. If Joe's phone bill was $71 under this promotional deal, how many minutes of phone calls did he make? Round to the nearest integer, if necessary. Thanks Sharon Brown This question is from textbook
You can put this solution on YOUR website! 15+.05x=71 this represents the $15 basic fee PLUS $.05 for every minute used (x) equals $71.
.05x=71-15
.05x=56
x=56/.05
x=1,120 minutes were used.
proof
15+.05*1,120=71
15+56=71
71=71
You can put this solution on YOUR website! You can start by writing the equation the expresses the total cost for the phone service: Where: C = total cost, F = basic fee($15) and x = the number of minutes at $0.05 per minute.
Making the appropriate substitutions, we get: Solve for x by subtracting 15 from both sides. Now divide both sides by 0.05 or... minutes.
Check: Substitute F = $15 and x = 1120 mins.