The probability is 1 in 4,000,000 that a single auto trip in the United States will result in a fatality. Over a lifetime , an average U.S. driver takes 50,000 trips. (a) What is the probability of a fatal accident over a lifetime? Explain your reasoning carefully. Hint: Assume independent events.
We use the complement event:
P(a fatal accident over a lifetime) = 1 - P(NO fatal accident over a lifetime)
So we consider first:
P(NO fatal accident over a lifetime)
We are given:
P(ONE single auto trip in the United States resulting in a fatality) =
= 0.00000025
Therefore
P(ONE single auto trip in the United States NOT resulting in a fatality) =
1-0.00000025 or 0.99999975
So
P(NO fatal accident over a lifetime) = P(NO fatal accident in the 50000 trips) =
P(No fatality on 1st trip AND
No fatality on 2nd trip AND
No fatality of 3rd trip AND
...AND
No fatality of 49999th trip AND
No fatality on 50000th trip)
Since all those events are independent we can simply multiply all
their probabilities together, which amounts to raising 0.99999975 to
the 50000th power:
and 0.9999997550000 = 0.987577799
But that is the probability of the complement event.
P(a fatal accident over a lifetime) = 1 - P(NO fatal accident over a lifetime)
so
P(a fatal accident over a lifetime) = 1 - 0.987577799 =
0.012422201 or rounding, about 0.0124
That's scary, isn't it? However there is relief in
the next question:
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why might the assumption of independence be violated?
When we assume independence, we are assuming that none of
our previous driving experiences when there were no fatal
accidents do not make it any less likely that we will have
an accident. We (and the insurance companies) know this
is NOT TRUE because as a rule, we become better drivers
when we have had more experience. This is why the
insurance premiums are much lower for adult drivers than
for teenage drivers. They know that the probability of
a fatal accident decreases as we get more experience
driveing -- and become more mature.
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(b) why might a driver be tempted not to use a seatbelt "just on this trip"?
Well, he should not be so tempted, lest it become a habit. But if
he if is really able to fail to buckle up only this once, then even
assuming independence above,
P(ONE single auto trip in the United States resulting in a fatality) =
= 0.00000025
and without independence it is an even smaller probability, and so he is
willing to take that small risk.
Edwin