SOLUTION: Lane invested $10,000, part at 15% and part at 14%. If the total interest at the end of the year is $1,430, how much did she invest at 15%?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Lane invested $10,000, part at 15% and part at 14%. If the total interest at the end of the year is $1,430, how much did she invest at 15%?      Log On


   

Question 125770: Lane invested $10,000, part at 15% and part at 14%. If the total interest at the end of the year is $1,430, how much did she invest at 15%?
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
let x="amount @ 15%", so 10000-x="amount @ 14%"

(15%)x+(14%)(10000-x)=1430 __.15x+1400-.14x=1430 __ .01x=30